- (i)
- b-a > 0
- (ii)
- b-a = 0
- (iii)
- -(b-a) > 0

Now we use process of elimination.

If b-a = 0 then this implies that b = a and then b^{2}.=.a^{2}
which contradicts the given statement

a^{2}.<.b^{2}.

If -(b-a) > 0 then a-b > 0 which implies that b.<.a. Therefore
b^{2}.<.a^{2} .(from 8) which
also contradict the
statement that a^{2}.<.b^{2}.

Hence b-a > 0 which implies that a.<.b.

Return to the tutorial