INTRODUCTORY EXERCISES


(4) A pilot flying at an altitude of 1200 feet is starting his approach. He is 4500 feet along his flight path from the runway.

(a) What is his horizontal distance (x) from the runway?

(b) What is his angle of approach ()?

SOLUTION:

(a) (4500)2 = (1200)2 + x2 x = 4337 feet (b) sin = 1200/4500 = 15o

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