Factor the following: 1) 4xReturn to the tutorial^{2}y + 16y - 8xy^{2}First term has factors of: 4, x, x, y Second term has factors of: 4, 4, y Third term has factors of: 4, 2, x, y, y Thus, there are two common factors of the expression: 4 and y. That is 4y. Once you take out this factor, you are left with x^{2}in the first term, 4 as the second term, and 2xy as the third term. Therefore: 4x^{2}y + 16y - 8xy^{2}= 4y(x^{2}+ 4y -2xy). 2) 5ab - 25b^{2}+ (5/2)a = 5[ab - 5b^{2}+ (1/2)a] --the common factor is 5 3) (1/2)y^{3}- 6xy^{2}- 11y = (1/2)y[y^{2}- 12xy - 22] --the common factor is (1/2)y 4) (x - 2)(x^{5}+ 3y) - (x + 3)(x - 2) + 53(x - 2)^{2}= (x - 2)[(x^{5}+ 3y) - (x + 3) + 53(x - 2)] --common factor is (x - 2) **Note: In later questions, not specifically focused on factoring, factoring is large part ofsimplifying.