
(6) Write each fraction as a sum or difference.
(a) (sqrt(3))(x) - 6 Where "sqrt" means the square root of
----------------
(sqrt(3))
(b) 3 + x2
--------
3
(c) 4x - 5x2 - 2x5
--------------
x2
(d) 3t2 + 5t
---------
2t3
(e) 9(x + 1) - 7
-------------
3(x + 1)
SOLUTION:
(a) (sqrt(3))(x) - 6 (sqrt(3))(x) - 6
---------------- = ------------ --------
(sqrt(3)) (sqrt(3)) (sqrt(3))
= x - 6
--------
(sqrt(3))
Now, to rationalize (refer to HINT), multiply the top and bottom of
the last term by (sqrt(3)):
= x - (6)(sqrt(3)) x - 6(sqrt(3))
------------------ = ----------
(sqrt(3))(sqrt(3)) 3
= x - 2(sqrt(3))
(b) 3 + x2 3 + x2 1 + x2
-------- = --- --- = ---
3 3 3 3
(c) 4x - 5x2 - 2x5 4x - 5x2 - 2x5
-------------- = ---- ----- ----
x2 x2 x2 x2
= 4 - 5 - 2x3
---
x
(d) 3t2 + 5t 3t2 + 5t 3 + 5
--------- = ---- ---- = --- ----
2t3 2t3 2t3 2t 2t2
(e) 9(x + 1) 7
---------- - ---------
3(x + 1) 3(x + 1)
7
= 3 - ---------
3(x + 1)