INTRODUCTORY EXERCISES - Symbol Maninpulation


(2) Factor. Simplify further where appropriate. For (d) and (e), indicate what values of the variable make the expression undefined.

 (a) 42t2 - 6yt - 96xt

 (b) x - 2x2

 (c) (5a + b)(a - b) - 11b(a - b)

 (d) y2 + y
     -------
      y + 1

 (e) 4x2 + 8x
     ---------
        2x3 

SOLUTION:
 (a)  42t2 - 6yt - 96xt
      6t(7t - y - 16x)

 (b)  x - 2x2
      x(1 - 2x)

 (c) (5a + b)(a - b) - 11b(a - b)
     (a - b)[(5a + b) - 11b]
     (a - b)(5a -10b)

 (d)  y2 + y      y(y + 1)    
     -------  =  ---------  =  y
      y + 1       (y + 1)
    
    To find the values of y that make the expression undefined, the denominator
    must NOT equal zero.
    Thus, (y + 1) not equal to 0
          (y) not equal to (-1)
    The expression is undefined when y = (-1).

 (e)  4x2 + 8x      4x(x + 2)      2(x + 2)
     ---------  =  ----------  =  ---------
        2x3            2x3            x2
    
      The expression is undefined when the denominator is zero, so in this
      case, x can not be equal to 0.  If x = 0, then the expression is
      undefined.



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