MODERATE EXERCISES


(4) Decompose the following fraction into partial fractions.

      3x - 13
   ------------
   6x2 - x - 12

SOLUTION:

      3x - 13         3x - 13          A     B
   ------------  =  ------------  =  ---- + ----
   6x2 - x - 12     (2x-3)(3x+4)     2x-3   3x+4

Find the common denominator to get:

      3x - 13       A(3x+4) + B(2x-3)
   ------------  =  -----------------
   6x2 - x - 12        (2x-3)(3x+4)

Therefore,

   3x - 13 = 3Ax + 4A + 2Bx -3B
           = (3A + 2B)x + (4A - 3B)

   3A + 2B = 3    ==>  A = 1 - 2B/3

   4A - 3B = -13  ==>  4(1 - 2B/3) - 3B = -13  ==> 4 - 8B/3 - 3B = -13
					       ==> -17B/3 = -17
					       ==>  B = 3

   A = 1 - 2(3)/3 = -1

The answer is:

      3x - 13        -1     3
   ------------  =  ---- + ----
   6x2 - x - 12     2x-3   3x+4



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