
(1) Find the constants A and B so that the given equation is true on its domain.
3x2 + 7x + 1 A B C ------------ = - + ----- - ------- x(x + 1)2 x x + 1 (x + 1)2SOLUTION:
Since 3x2 + 7x + 1 A B C
------------ = - + ----- - -------
x(x + 1)2 x x + 1 (x + 1)2
We can find a common denominator on the left to get:
3x2 + 7x + 1 A(x + 1)2 + Bx(x + 1) - Cx
------------ = ---------------------------
x(x + 1)2 x(x + 1)2
Therefore we see that 3x2 + 7x + 1 = Ax2 + 2Ax + A + Bx2 + Bx - Cx
= (A + B)x2 + (2A + B - C)x + A
Therefore
A = 1
2A + B - C = 7 ==> 2(1) + B - C = 7
A + B = 3 ==> 1 + B = 3 ==> B = 2
And 2 + 2 - C = 7 ==> C = -3
So we get:
3x2 + 7x + 1 1 2 -3
------------ = - + ----- - -------
x(x + 1)2 x x + 1 (x + 1)2
3x2 + 7x + 1 1 2 3
------------ = - + ---- + -------
x(x+1)2 x x + 1 (x + 1)2