
(1) Find the constant A and B so that the given equation is true on its domain.
(a) 9x + 21 A B
-------------- = ------- + -------
(x + 5)(x - 3) x + 5 x - 3
(b) 3x2 + x A Bx + C
--------------- = ------ + -------
(x - 2)(x2 + 3) x - 2 x2 + 3
SOLUTION:
(a) 9x + 21 A(x - 3) + B(x + 5)
-------------- = -------------------
x2 + 2x - 15 x2 + 2x - 15
Ax - 3A + Bx + 5B
= -------------------
x2 + 2x - 15
(A + B)x + (5B - 3A)
= ----------------------
x2 + 2x - 15
Next, we solve for the unknowns in the two equations we obtain:
A + B = 9
5B - 3A = 21
We find that A = 3 and B = 6.
(b) 3x2 + x A Bx + C
------------- = ----- + -------
(x -2)(x2 + 3) x - 2 x2 + 3
A(x2 + 3) + (Bx + C)(x-2)
= -------------------------
(x - 2)(x2 + 3)
Ax2 + 3A + Bx2 - 2Bx + Cx - 2C
= ------------------------------
(x - 2)(x2 + 3)
(A + B)x2 +(-2B + C)x + (3A - 2C)
= ---------------------------------
(x - 2)(x2 + 3)
Next, we solve for the unknowns in the three equations we obtain:
A + B = 3 ===> B = 3 - A
-2B + C = 1 ===> -2(3 - A) + C = 1 ===> -6 + 2A + C = 1 ===> C = 7 - 2A
3A - 2C = 0 ===> 3A - 2(7 - 2A) =0 ===> 3A - 14 +4A = 0 ===> 7A = 14
Therefore A = 2 ,B =3 - 2 =1 and C = 7 - 2(2) = 3