
ADVANCED EXERCISES
Decompose each fraction into partial fractions:
(4) 4x2 + 5x - 9
------------
x3 -12x + 9
SOLUTION:
Let 4x2 + 5x - 9 A Bx + C
------------ = ---- + ------------
x3 - 12x + 9 x-3 x2 + 3x - 3
We then get that:
4x2 + 5x - 9 = A(x2 + 3x - 3) + (Bx + C)(x-3)
= Ax2 + 3Ax - 3A + Bx2 - 3Bx + Cx - 3C
= (A + B)x2 + (3A - 3B + C)x + (-3A - 3C)
This implies :
A + B = 4 ==> A = 4 - B
3A - 3B + C = 5 ==> 3(4-B) - 3B + C = 5 ==> C = 6B - 7
-3A - 3C = -9 ==> -3(4-B) - 3(6B-7) = -9 ==> -12 + 3B - 18B + 21 = -9
==> -15B = -18
==> B = 6/5
A = 4 - 6/5 = 14/5
C = 6(6/5) - 7 = 1/5
The answer is:
4x2 + 5x - 9 14/5 6x/5 + 1/5
------------ = ---- + ------------
x3 - 12x + 9 x-3 x2 + 3x - 3
14 6x + 1
= ------ + ---------------
5(x-3) 5(x2 + 3x - 3)
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