
(3) Solve the following absolute value inequalities. Also, graph the solution on the number line.
(a) 5SOLUTION:|x + 1| (b) |4x + 20|
12 (c)
(d) |x2 - 2x|
0
(a) 5|x + 1| 5
x + 1 or -5
x + 1 x
4 x
-6 _________________
_ _ _ _ _ _ _ _ _ _ _
____________________ -6 4 (b) |4x + 20|
12 4x + 20
12 or 4x + 20
-12 4x
-8 4x
-32 x
-2 x
-8 _ _ _ _ _ _
___________________
_ _ _ _ _ _ -8 -2 (c)
1/3|x + 1| < 4/5 |x + 1| < 12/5 x + 1 < 12/5 or x + 1 > -12/5 x < 7/5 x > -17/5 _ _ _ _ _ _o________________________o_ _ _ _ _ _ -17/5 7/5 (d) |x2 - 2x| > 0 Since absolute values are ALWAYS greater than or equal to 0, we can find out where x2 - 2x = 0 and eliminate those points. x2 - 2x = 0 x(x-2) = 0 x = 0 or x-2 = 0 x = 2 Therefore the answer is (-
,0)
(0,2)
(2,
) _______________o__________o_________________ 0 2