
(2) Solve each inequality. (a) (x + 3)(x - 4)HINT: If the inequality isn't already factored, with 0 on one side of the inequality, then manipulate the expression so that that is the situation.0 (b) 9/4
x2 (c) 3x2 - 2x - 6
2x2 - 6x - 1 (d) x - 2 ------
0 2x + 5 (e) 2x ------
0 x2 + 5
Then, note that the sign of each factor determines the sign of the product (or in the case of a quotient, the sign of the factors of the numerator and denominator).
So for example, in question (a), if the product is to be positive (forget about the equals sign for a moment), then either x+3 and x-4 must be positive, or both must be negative. You should be able to determine when x+3> 0 and x-4 > 0; then when x+3 < 0 and x-4 < 0. (Eventually you should obtain two non-overlapping intervals.) Then note that the product equals 0 when x=-3 or x=4, so these numbers should be in your solution set.