
SOLUTION:(1) Find all asymptotes for the given functions. 2x2 + 3x (a) g(x) = --------- 3x2 - 48 5x4 (b) R(x) = ------------ 2x2 + 3x - 2 3x (c) F(x) = ------------- x4 + 2x2 + 1 x2 + 2 (d) H(x)= ------ x - 1
2x2 + 3x
(a) g(x) = ---------
3x2 - 48
3x2 - 48 = 0
x2 = 16
x =
4(vertical asymtotes)
2x2/x2 + 3x/x2
g(x) = --------------
3x2/x2 - 48/x2
2 + 3/x
= ---------
3 - 48/x2
y= 2/3 (horizontal asymtote)
The asymtotes of g(x) are x = 4, x = -4 and y = 2/3
(b) 5x4
R(x) = ------------
2x2 + 3x - 2
2x2 + 3x - 2 = 0
(x + 2)(2x - 1) = 0
x = -2 or x = 1/2 (vertical asymtotes)
5x4/x4
R(x) = --------------------
2x2/x4 + 3x/x4 - 2/x4
5
= ------------------
2/x2 + 3/x3 - 2/x4
==> no horizontal asymtotes
There are two vertical asymtotes, one at x = -2 and the other at x = 1/2.
(c) 3x
F(x) = ------------
x4 + 2x2 + 1
x4 + 2x2 + 1 = 0
(x2 + 1)2 = 0
x2 = -1 impossible. Therefore no vertical asymtotes
3x/x4
F(x) = --------------
x4/x4 + 2x2/x4 + 1/x4
3/x3
= -----------
1 + 2/x2 + 1/x4
y = 0 is a horizontal asymtote.
There is one asymtote which is at y = 0.
(d)
x2 + 2
H(x)= ------
x - 1
x - 1 = 0 ==> x = 1 is a vertical asymtote.
x2/x2 + 2/x2 1 + 2/x2
H(x)= ------------ = ----------
x/x2 - 1/x2 1/x - 1/x2
==> no horizontal asymptotes.
There is only one asymtote which is a x = 1.