
1SOLUTION:(1) Given f(x) = ---, evaluate and simplify the following:
(a) f(x) - f(5) ----------- x - 5 (b) f(9 + h) - f(9) --------------- h (c) f(x + h) - f(x) --------------- h
1 1 --- - --- (a) f(x) - f(5)![]()
----------- = ----------- x - 5 x - 5 After substituting as above, rationalize the fractions in the numerator: 1
1
--- * --- - --- * ---
![]()
![]()
![]()
= ----------------------- x - 5
![]()
--- - --- x 5 = ----------- x - 5 Next, get rid of the complex fraction:
5
x 5
x
--- * --- - --- * --- ----- - ----- x 5 5 x 5x 5x = ----------------------- = --------------- x - 5 x - 5 5
- x
------------- 5x 5
- x
5
- x
= ----------- = ----------- = ----------- x - 5 5x(x - 5) 5x2 - 25x Then rationalize the numerator: 5
- x
5
+ x
= ------------ * ----------- 5x2 - 25x 5
+ x
25x - 5x2 = ----------------------- (5x2 - 25x)(5
+ x
) Finally, factor a -1 out of the numerator and reduce: -(5x2 - 25x) -1 = ----------------------- = ------------- (5x2 - 25x)(5
+ x
) 5
+ x
1 1 1 1 ----- - --- ----- - --- (b) f(9 + h) - f(9)
![]()
![]()
3 --------------- = ------------- = ------------- h h h 1 3 1
3
----- * --- - --- * ----- ------- - -------
3 3
3
3
= ---------------------------- = ------------------- h h 3 -
-------------- 3
3 -
= ---------------- = ------------ h 3h(
) 3 -
3 +
= ------------ * ------------ 3h(
) 3 +
9 - (9 + h) 9 - 9 - h = ------------------------ = ------------------------ 3h(
)(3 +
) 3h(
)(3 +
) -h -1 = ------------------------ = ---------------------- 3h(
)(3 +
) 3(
)(3 +
) 1 1 ------- - --- (c) f(x + h) - f(x)
![]()
--------------- = --------------- h h 1
1
------- * --- - --- * -------
![]()
![]()
![]()
= ----------------------------- h
![]()
--------- - ---------
![]()
= ------------------------ h
-
--------------
![]()
-
= ---------------- = ------------- h h
![]()
-
![]()
+
= ------------- * ------------- h
![]()
+
x- (x + h) x - x - h = ------------- = ------------- h
h
-h -1 = ------------- = ------------- h
h
![]()