
(4) Find the equation of each circle described below:
(a) center at the origin and passing through (4,7) (b) center at (3,-2) and has y-intercept at -1. (c) endpoints of a diameter are (-2,3) and (3,-1). (d) center at (3,5) and tangent to the x-axis.SOLUTION:
(a) radius2 = (7 - 0)2 + (4 - 0)2
= 49 + 16 = 65
(x - 0)2 + (y - 0)2 = radius2
x2 + y2 = 65
(b) (x - 3)2 + (y + 2)2 = A
(0 - 3)2 + (-1 + 2)2 = A
9 + 1 = A
A = 10
(x - 3)2 + (y + 2)2 = 10
(c) diameter2 = (3 - (-2))2 + (-1 - 3)2
= 52 + 42
= 25 + 16 = 41
radius2 = diameter2/4 = 41/4
using the midpoint formula to find the center of the circle we get:
x = (3 - 2)/2 = 1/2
y = (-1 + 3)/2 = 2/2 = 1
(x - 1/2)2 + (y - 1)2 = 41/4
(d) (x - 3)2 + (y - 5)2 = 25