INTRODUCTORY EXERCISES


(2) Using the basic rules BR1 - BR12, show that the following property of real numbers holds:

If a > 0, then 1/a > 0.
SOLUTION:

We are assuming a > 0. This implies 1/a exists (BR-8) and 1/a not equal to 0 (otherwise, (1/a)a would be 0, not 1). Thus, by BR-10, either 1/a > 0 or -1/a > 0. We now show that -1/a > 0 is impossible. If -1/a > 0 were true, then, since a > 0 also, we must have

(-1/a)a > 0 BR-12.

But (-1/a)a = -1, so this contradicts 1 > 0. Thus, we must conclude that 1/a > 0.


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