(2) Using the basic rules BR1 - BR12, show that the following property of real numbers holds:
SOLUTION:If a > 0, then 1/a > 0.
We are assuming a > 0. This implies 1/a exists
(BR-8) and 1/a
0 (otherwise, (1/a)a would be 0,
not 1). Thus, by BR-10, either 1/a > 0 or
-1/a > 0. We now show that
-1/a > 0 is impossible. If
-1/a > 0 were true, then, since a > 0 also, we
must have
(-1/a)a > 0 BR-12.
But (-1/a)a = -1, so this contradicts 1 > 0. Thus, we must conclude that 1/a > 0.