MODERATE EXERCISES

(2) Solve for x. 


 (a) |x2 - 1| = 3

 (b) |x2 + 3x| = 0
SOLUTION: 

 (a) |x2 - 1| = 3

     ==>  x2 - 1 = 3  or  x2 - 1 = -3

          x2 = 4         x2 = -2

          x = 2         impossible


 (b) |x2 + 3x| = 0

     ==>  x2 + 3x = 0

          x(x + 3) = 0

          x = 0 or x = -3

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