Solve for a and b in the given triangle.
- Since the sum of the angles of the triangle is 180o, we get that
B = 60o. Now
we can find a by using the trigonometric ratio sin = opp/hyp. Therefore:
sin30o = a/12
To find b, we can use cos30o or sin60o, we get the
same answer. Let's use
a = 12 * sin30o = 12(1/2) = 6
cos30o = b/12
b = 12 * cos30o = 12(/2) = 6
Find the value of sin240o and cos495o.
- The reference angle is going to be 240o - 180o =
60o. But with a 240o angle, sin is negative.
Therefore we get:
sin240o = -sin60o = -/2
For 495o the coterminal angle is 135o. The reference
angle is 180o - 135o = 45o. Since the
sign of cos135o is negative, we get:
cos495o = cos135o = -cos45o =
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