1) log151 = 0Return to the tutorialSolution: 150 = 1 That is, any number or expression raised to the power of 0 is defined as being equal to 1. 2) log55 = 1 Solution: 51 = 5 That is, any expression/number raised to the power of one is the expression/number itself (unchanged). 3) log33x = x Solution: 3x = 3x 4) eln4 = 4 Solution: Recall that if you do something to one side of an equation, you must do the same thing to the other side, in order for the equation to remain the same. Step 1: take the ln of both side: ln(eln4) = ln(4) Refer to property #7: ln(4)[ln(e)] = ln(4) ln(e) = 1 by definition: ln(4) = ln(4) We get the same expression on both sides so the original equation is true. 5) log107 + log104 = log1028 Solution: Left hand side of the equation: i) log107 = 0.845 ii) log104 = 0.602 iii) 0.845 + 0.602 = 1.447 Right hand side of the equation: iv) log28 = 1.447 also Thus, 1.447 = 1.447 which we know is correct. 6) ln2 - ln5 = ln(2/5) Solution: Left hand side of equation: i) ln2 = 0.693 ii) ln5 = 1.609 iii) ln2 - ln5 = 0.693 - 1.609 = -0.916 Right hand side of equation: iv) ln(2/5) = ln(0.4) = -0.916 Thus, -0.916 = -0.916 which we know to be correct. 7) log1023 = 3log102 Solution: log10(8) = 0.903 while 3log102 = 3(0.301) = 0.903 Thus, both sides of the equation equal the same number which means the original statement must be true.