Example 1:

Show that the point P(SQRT(3)/3, is on the unit circle.

Solution:
We need to show that this point satisfies the equation of the unit circle, that is, x2_+_y2_=_1.

(SQRT(3)/3)^2 + 
	(SQRT(2)/SQRT(3))^2 = 3/9+2/9 = 1/3+2/3 = 1

Therefore P is on the unit circle.



Example 2:

The point P(SQRT(3)/2, y) is on the unit circle in quadrant IV. Find its y-coordinate.

Solution:
Since the point is on the unit circle, we have:
(SQRT(3)/2)^2 + y^2 = 1
y2 = 1 - 3/4 = 1/4
y = +-1/2
Since the point is in quadrant IV, its y-coordinate must be negative, so y.=.-1/2.
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